Kotlin – Convert Object to/from XML File (XML String) by Jackson

In the tutorial, we will show how to convert XML String/File to Object and versus by Kotlin language with Jackson.

Jackson XML Dataformat

For serialize/deserialize Object to XML and versus, we use ‘Jackson Dataformat XML’ dependency:


Write Kotlin object to XML

Create model:

package com.javasampleapproach.kotlin.xml.model

data class Address(
	val street: String = "",
	val postcode: String = ""
package com.javasampleapproach.kotlin.xml.model

data class Customer(
	val name: String = "",
	val age: Int = -1,
	val address: Address? = null

Kotlin object to XML String

Use writeValueAsString(obj: Object): String:

val xmlMapper = XmlMapper()
val strObject = xmlMapper.writeValueAsString(object)

Kotlin object to XML File

Use writeValue(File resultFile, Object value): Unit:

val xmlMapper = XmlMapper()
xmlMapper.writeValue(File(pathFile), object)

Program – Kotlin object to XML

package com.javasampleapproach.kotlin.xml

import java.io.File
import java.io.IOException
import com.fasterxml.jackson.core.JsonGenerationException
import com.fasterxml.jackson.core.JsonProcessingException
import com.fasterxml.jackson.databind.JsonMappingException
import com.fasterxml.jackson.databind.SerializationFeature
import com.fasterxml.jackson.dataformat.xml.XmlMapper
import com.javasampleapproach.kotlin.xml.model.Customer
import com.javasampleapproach.kotlin.xml.model.Address

fun main(args: Array) {
	val customer = Customer("Mary", 37, Address("NANTERRE CT", "77471"))
	// 1. Write Object to XML String
    val xml = write2XMLString(customer)
*/ // 2. Write Object to XML File val pathFile = System.getProperty("user.dir") + "\\customer.xml" write2XMLFile(customer, pathFile) // -> content of customer.xml file: /* Mary 37
*/ } /* * Convert Object to XML String */ fun write2XMLString(obj: Any): String { val xmlMapper = XmlMapper() // use the line of code for pretty-print XML on console. We should remove it in production. xmlMapper.enable(SerializationFeature.INDENT_OUTPUT); return xmlMapper.writeValueAsString(obj) } /* * Write Object to XML file */ fun write2XMLFile(obj: Any, pathFile: String) { val xmlMapper = XmlMapper() // use the line of code for pretty-print XML on console. We should remove it in production. xmlMapper.enable(SerializationFeature.INDENT_OUTPUT) xmlMapper.writeValue(File(pathFile), obj) }

Convert XML to Kotlin object

XML String to Kotlin object

Use readValue(content: String, valueType: Class<*>):

val xmlString = 	"" + 
					"  Mary" + 
					"  37" + 
" + " NANTERRE CT" + " 77471" + "
" + "
" val xmlMapper = XmlMapper() val obj = xmlMapper.readValue(xmlString, cls)

XML File to Kotlin object

Use readValue(src: File, valueType: Class<*>):

val xmlMapper = XmlMapper()
val obj = xmlMapper.readValue(new File(pathFile), cls)

Program – XML to Kotlin object

package com.javasampleapproach.kotlin.model

import java.io.File;
import java.io.IOException;
import com.fasterxml.jackson.core.JsonGenerationException;
import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.JsonMappingException;
import com.fasterxml.jackson.databind.SerializationFeature;
import com.fasterxml.jackson.dataformat.xml.XmlMapper
import com.javasampleapproach.kotlin.xml.model.Customer

fun main(args: Array) {
	 * 1. Convert String XML to Object
	val xmlString = 	"" + 
						"  Mary" + 
						"  37" + 
" + " NANTERRE CT" + " 77471" + "
" + "
" var customer = convertXmlString2DataObject(xmlString, Customer::class.java) println(customer) // -> Customer[name=Mary, age=37, Address[street=NANTERRE CT, postcode=77471]] /* * 2. Convert XML File to Object */ val pathFile = System.getProperty("user.dir") + "\\customer.xml" customer = convertXmlFile2DataObject(pathFile, Customer::class.java) println(customer) // -> Customer[name=Mary, age=37, Address[street=NANTERRE CT, postcode=77471]] } fun convertXmlString2DataObject(xmlString: String, cls: Class<*>): Any { val xmlMapper = XmlMapper() return xmlMapper.readValue(xmlString, cls) } fun convertXmlFile2DataObject(pathFile: String, cls: Class<*>): Any{ val xmlMapper = XmlMapper() return xmlMapper.readValue(File(pathFile), cls) }

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